If cos Θ = negative 4 over 7, what are the values of sin Θ and tan Θ?

Given cos theta is equal to - 4 / 7 then we can conclude that theta is in the second and third quadrants. In this case, the other leg is equal to square root of (7^2 - 4^2) equal to square root of 33. In this case, sin theta can be equal to + - square root of 33 / 7 and tan theta is equal to + - square root of 33 / 4.