A group of 8 friends plan to go watch a movie but they only have 5 tickets. How many different combinations of 5 friends could possibly receive the ticket?

A) 13

B) 10

C) 56

D) 64

Answer: option C) 56.

Explanation:

1) You have to find the number of ways how you can combine 5 friend (this is form groups of 5 people) out of a group of 8.

2) That is the 5C8

3) The formula for combinatory is: nCm = m! / [ n! (m - n) !]

4) So for m = 8 and n = 5 you get:

5C8 = 8! / [5! (8 - 5) ! ] = 8*7*6*5! / [ 5! * 3!] = 8*7*6 / [ 3*2*1] = 8*7 = 56

So, the answer is the option C) 56.

b cause 8*5=40 but if there are only 8 and 5 ticket then what you would do is ... - 8*-5=-40