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1 October, 08:45

Find the sum of 12th term of the following AP series 7,11 and 15.

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  1. 1 October, 08:59
    0
    Answer:the sum of the 12th term of the AP is 348

    Step-by-step explanation:

    7,11,15

    Common difference=d=11-7

    d=4

    First term=7

    Using the formula

    Sn=n/2 x (2a+d x (n-1))

    S12=12/2 x (2x7+4x (12-1))

    S12=6 x (14+4x11)

    S12=6 x (14+44)

    S12=6 x 58

    S12=348
  2. 1 October, 08:59
    0
    It is adding 4 each time.

    Just calculate the first 12 terms and add them up.

    Term 1 = 7 + 4*0 = 7

    Term 2 = 7 + 4*1 = 11

    Term 3 = 7 + 4*2 = 15

    Term 4 = 7 + 4*3 = 19

    Term 5 = 7 + 4*4 = 23

    Term 6 = 7 + 4*5 = 27

    Term 7 = 7 + 4*6 = 31

    Term 8 = 7 + 4*7 = 35

    Term 9 = 7 + 4*8 = 39

    Term 10 = 7 + 4*9 = 43

    Term 11 = 7 + 4*10 = 47

    Term 12 = 7 + 4*11 = 51

    Sum of first 12 terms = 348
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