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1 March, 04:59

what is the 60th term in an arithmetic sequence with the first term equal 1 and the constant difference equals 7

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  1. 1 March, 05:21
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    Answer: 60th term of sequence is 414

    Step-by-step explanation: An = a + (n-1) d

    Here n=60, a=1, d=7

    A60 = 1 + (60-1) 7

    A60 = 1 + (59) 7

    A60 = 1+413

    A60 = 414

    Hence 60th term of sequence is 414
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