If p, q are zeroes of polynomial f (x) = 2x^2-7x+3, find the value of p^2+q^2

p^2 + q^2 = 22/9.

Step-by-step explanation:

For a quadratic function ax^2 + bx + c if the zeroes are A and B then

A + B = - b/a and AB = c/a.

2x^2 - 7x + 3

Now p and q are the zeroes of the above function so

p + q = 7/3 and pq = 3/2.

Now p^2 + q^2 = (p + q) ^2 - 2pq

= (7/3) ^2 - 2 * 3/2

= 49/9 - 3

= 49/4 - 27/9

= 22/9.