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Georgia Sheppard
Mathematics
26 June, 00:12
What's substitution for y=4x-1; y=2x-5
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Luciana Conley
26 June, 00:39
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y = 4x - 1; y = 2x - 5
Step: Solve y = 4x - 1 for y:
Step: Substitute 4x - 1 for y in y = 2x - 5:
y = 2x - 5
4x - 1 = 2x - 5
4x - 1 + - 2x = 2x - 5 + - 2x (Add - 2x to both sides)
2x - 1 = - 5
2x - 1 + 1 = - 5 + 1 (Add 1 to both sides)
2x = - 4
2x / 2 = - 4 / 2 (Divide both sides by 2)
x = - 2
Step: Substitute - 2 for x in y = 4x - 1:
y = 4x - 1
y = (4) (-2) - 1
y = - 9 (Simplify both sides of the equation)
Answer: y = - 9 and x = - 2
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