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18 December, 17:57

What is an equation of the line that passes through (0, 8) and (4, 0) ?

y = 2 x + 8

y = 2 x + 4

y = - 2 x + 4

y = - 2 x + 8

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  1. 18 December, 18:03
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    Step-by-step explanation:

    Say y=ax+b. It goes through (0,8) and (4,0). Therefor we can say 8=a (0) + b which gives us b=8. Then we fill in (4,0) which results in 0=a (4) + 8. Given that, a=-2. so y=-2+8
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