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4 January, 08:18

A code is made up of a letter (A-Z) and two digits (0-9). The digit can be repeated. How many possible codes exist? 2600 260 46 28

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  1. 4 January, 08:21
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    2600.

    Step-by-step explanation:

    There are 26 letters.

    Also there are 10P2 permutations of the digits 0-9

    10P2 = 10! / (10-2) ! = 90.

    There are 10 repeated digits.

    So the number of possible codes are 26 * (90 + 10)

    = 2600.
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