A train ticket in a certain city is $2.00. People who use the train also have the option of purchasing a frequent rider pass for $18.00 each month. With the pass, each ticket costs only $1.25. Determine the number of times in a month the train must be used so that the total monthly cost without the pass is the same as the total monthly cost with the pass.

a. 26 times

b. 24 times

c. 23 times

d. 25 times

the number of times in a month the train must be used, so that the total monthly cost without the pass is the same as the total monthly cost with the pass, is b. 24 times

Step-by-step explanation:

in normal purchase, train ticket (A) = $2.00

using frequent pass,

frequent pass (P) = $18

train ticket using frequent pass (B) = $1.25

Now, let assume the number of times in a month the train must be used = M

so,

A x M = P + (B x M)

$2.00 x M = $18 + ($1.25 x M)

($2.00 x M) - ($1.25 x M) = $18

M x ($2.00 - $1.25) = $18

M = $18 : $0.75

M = 24

Thus, the number of times in a month the train must be used is 24 times