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19 March, 03:05

Suppose an investment of $1,800 doubles in value every 7 years. How much is the investment worth after 42 years?

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Answers (2)
  1. 19 March, 03:23
    0
    X=2^n (1800)

    x=2^6 (1800)

    x=$115,200
  2. 19 March, 03:26
    0
    Divide 42 by 7 which equals 6. So 1,800 times 6 = 10,800.
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