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1 August, 04:59

G solve 2x 00 + 10x = 3u (t - 12) - 5δ (t - 4) with x (0) = - 1 and x 0 (0) = - 2.

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  1. 1 August, 05:03
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    {2 x*0 + 10 x = 3 u (t - 12) - (5 δ (t - 4)) x (0) = - 1, x*0*0 = - 2}

    {10 x = 3 u (t - 12) - 5 x (0) δ (t - 4) = - 1, False}
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