Two cubes are tossed. Find P (only one shows a 2).

The probability that only one shows a 2.

There are 36 different outputs (6x6) = 36

There are 6 combinations where the first cube shows a 2, these are 2,1; 2,2; 2,3; 2,4; 2,5; and 2.6

There are 6 combinations where the second cube shows a 2: 1,2; 2,2; 3,2; 4,2; 5,2; and 6,2.

Of those one combination on each set shows two 2.

Then the number of combinations with only one 2 are 6 - 1 + 6 - 1 = 10

Now the probabilit is 10 out of 36 = 10 / 36 = 5 / 18