The perimeter of a rectangle is 900 yards. What are the dimensions of the rectangle if the length is 70 yards more than the width?

Perimeter=2 (l+b)

=900=2 (l+b)

let width be x

=900=2 (70+x+x)

=900=2 (70+2x)

=900:2=70+2x

=450=70+2x

=450-70=2x

=380=2x

=380:2=*

x=190

so, width = x

=width=190

breadth=190+70

=breadth=260