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11 August, 21:23

whats the algebraic equation for: Jorge has some dimes and quarters. He has 10 more dimes than quarters and the collection of coins is worth $2.40. How many dime and quarters does Jorge have?

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  1. 11 August, 21:26
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    4 quarters and 14 dimes

    Step-by-step explanation:

    Let x be quarters and since Jorge has 10 more dimes than quarters you can say x + 10. 25 is the quarters and the 10 is the dimes.

    25x + 10 (x+10) = 240

    25x + 10x + 100 = 240

    35x = 140

    x = 4

    Multiply 4 and 0.25 and you get 1.00. Subtract 1.00 from 2.40 to get 1.40. Divide that by 10 (amount of dime) to get 14.
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