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11 January, 21:19

X = (y+2) ^2 solve the equation

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Answers (2)
  1. 11 January, 21:28
    0
    x = y^2+4y+4

    Step-by-step explanation:

    x = (y+2) (y+2)

    x = y^2+2y+2y+4

    x = y^2+4y+4
  2. 11 January, 21:49
    0
    X = y^2 + 4y + 4

    Y = (√X) - 2

    Step-by-step explanation:

    X = (Y+2) ^2

    X = (Y+2) (Y+2)

    X = Y^2 + 4y + 4

    X = (Y+2) ^2

    √X = √ (Y+2) ^2 (taking the root of both sides cancels the exponent)

    √X = Y+2

    -2 - 2

    (√X) - 2 = Y

    or

    Y = (√X) - 2
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