X = (y+2) ^2 solve the equation

Question

Fitzpatrick

Mathematics

11 January, 21:19

X = (y+2) ^2 solve the equation

+4

Answers (2)

Know the Answer?

Ishaan Barr · Answer 1

x = y^2+4y+4

Step-by-step explanation:

x = (y+2) (y+2)

x = y^2+2y+2y+4

x = y^2+4y+4

Lamont Salazar · Answer 2

X = y^2 + 4y + 4

Y = (√X) - 2

Step-by-step explanation:

X = (Y+2) ^2

X = (Y+2) (Y+2)

X = Y^2 + 4y + 4

X = (Y+2) ^2

√X = √ (Y+2) ^2 (taking the root of both sides cancels the exponent)

√X = Y+2

-2 - 2

(√X) - 2 = Y

or

Y = (√X) - 2