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Fitzpatrick
Mathematics
11 January, 21:19
X = (y+2) ^2 solve the equation
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Ishaan Barr
11 January, 21:28
0
x = y^2+4y+4
Step-by-step explanation:
x = (y+2) (y+2)
x = y^2+2y+2y+4
x = y^2+4y+4
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Lamont Salazar
11 January, 21:49
0
X = y^2 + 4y + 4
Y = (√X) - 2
Step-by-step explanation:
X = (Y+2) ^2
X = (Y+2) (Y+2)
X = Y^2 + 4y + 4
X = (Y+2) ^2
√X = √ (Y+2) ^2 (taking the root of both sides cancels the exponent)
√X = Y+2
-2 - 2
(√X) - 2 = Y
or
Y = (√X) - 2
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