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Mulligan
Mathematics
7 September, 05:44
Find the sum: (3x^2+2x+3) + (x^2+x+1)
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7 September, 06:04
0
4x2 + 3x + 4
Step-by-step explanation:
Step-1 : Multiply the coefficient of the first term by the constant 4 • 4 = 16
Step-2 : Find two factors of 16 whose sum equals the coefficient of the middle term, which is 3.
-16+-1=-17
-8+-2=-10
-4+-4=-8
-2+-8=-10
-1+-16=-17
1+16=17
2+8=10
4+4=8
8+2=10
16+1=17
Final result:
4x2 + 3x + 4
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