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24 July, 19:55

Use the method of completing the square to solve y²+y-7=0

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Answers (2)
  1. 24 July, 20:00
    0
    y=sqrt (29) / 2-1/2, - sqrt (29) / 2-1/2

    Step-by-step explanation:

    y^2+y-7=0

    completing the square,

    (b/2) ^2 = (1/2) ^2=1/4

    (y+1/2) ^2=7+1/4

    (y+1/2) ^2=28/4+1/4

    (y+1/2) ^2=29/4

    y+1/2=sqrt (29/4)

    y=sqrt (29/4) - 1/2

    y=sqrt (29) / 2-1/2

    y=-sqrt (29) / 2-1/2
  2. 24 July, 20:16
    0
    y = sqrt (29) / 2 - 1/2 or y = - 1/2 - sqrt (29) / 2

    Step-by-step explanation:

    Solve for y:

    y^2 + y - 7 = 0

    Add 7 to both sides:

    y^2 + y = 7

    Add 1/4 to both sides:

    y^2 + y + 1/4 = 29/4

    Write the left hand side as a square:

    (y + 1/2) ^2 = 29/4

    Take the square root of both sides:

    y + 1/2 = sqrt (29) / 2 or y + 1/2 = - sqrt (29) / 2

    Subtract 1/2 from both sides:

    y = sqrt (29) / 2 - 1/2 or y + 1/2 = - sqrt (29) / 2

    Subtract 1/2 from both sides:

    Answer: y = sqrt (29) / 2 - 1/2 or y = - 1/2 - sqrt (29) / 2
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