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Today, 18:53

Let / / (E=t { x|x^{2}-3x=-2 }//), / / (H=t { 1,2 }//). Then a. NOU193131382 / / (E//cap E=O//) b. / / (H//cup E = t { 1,3 }//) c. / / (H//cup E=O//) d. E=H

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  1. Today, 19:20
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    d. E=H

    Step-by-step explanation:

    The set E of values of x that satisfy x²-3x=-2 is {1, 2}, which matches set H.

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    You can try them and see.
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