Sam and Jeremy have ages that are consecutive odd integers. The product of their ages is 783, which equation could be used to find Jeremy's age, j, if he is the younger man?

(2x+1) = Jeremy's age

(2x+3) = Sam's age.

we suggest this equation:

(2x+1) (2x+3) = 783

4x²+6x+2x+3=783

4x²+8x-780=0

x²+2x-195=0

We solve this quadratic equation:

x=[-2⁺₋√ (4-4*1 * (-195)) ]/2 = (-2⁺₋28) / 2

x₁ = (-2-28) / 2=-15 this solution is not valid.

x₂ = (-2+28) / 2=13

Jeremy's age=2x+1=2*13+1=27

Sam's age=2x+3=2*13+3=29