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22 January, 22:45

How to draw a line that passrs through the origion and has a slope of 2/3?

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  1. 22 January, 23:05
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    The origin is (0,0)

    y = mx + b

    slope (m) = 2/3

    (0,0) ... x = 0 and y = 0

    now we sub and find b, the y int

    0 = 2/3 (0) + b

    0 = b

    so ur equation is y = 2/3x + 0 ... or just y = 2/3x
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