Julia has two children who are four years apart in age. Julia is four times

older than her youngest child. The sum of the ages of Julia and her children

is 76 years. Use the 5-D Process to find the ages of Julia and each of her

children.

Question

Caprice

Mathematics

28 March, 23:41

Julia has two children who are four years apart in age. Julia is four times

older than her youngest child. The sum of the ages of Julia and her children

is 76 years. Use the 5-D Process to find the ages of Julia and each of her

children.

+4

Answers (1)

Know the Answer?

Miranda Norman · Answer 1

Julia is 48. Her youngest child is 12 and her oldest is 16.

Step-by-step explanation:

I guessed the youngest child's age (12) then I added 4 that equaled 16. Then I multiplied 12 by 4 which is 48. 48 plus 12 plus 16 equals 76. As for the 5d process I have no idea what that is your on your own for show work.

Julia has two children who are four years apart in age. Julia is four timesolder than her youngest child. The sum of the ages of Julia and her childrenis 76 years. Use the 5-D Process to find the ages of Julia and each of herchildren.

Julia has two children who are four years apart in age. Julia is four times

older than her youngest child. The sum of the ages of Julia and her children

is 76 years. Use the 5-D Process to find the ages of Julia and each of her

children.