Ask Question
MathematicsMathematics
17 January, 15:00

In a triangle ABC, AB = 7, AC = 8, BC = 3, what is cos (A) ?

+1
Answers (1)
  1. 17 January, 15:24
    0
    Use the cosine rule.

    c=AB=7

    b=AC=8

    a=BC=3

    a^2=b^2+c^2-2bc (cos (A))

    =>

    cos (A) = (b^2+c^2-a^2) / (2bc)

    = (7^2+8^2-3^2) / (2*7*8)

    =13/14

    =0.9286
Know the Answer?
Not Sure About the Answer?
Find an answer to your question 👍 “In a triangle ABC, AB = 7, AC = 8, BC = 3, what is cos (A) ? ...” in 📗 Mathematics if the answers seem to be not correct or there’s no answer. Try a smart search to find answers to similar questions.
Search for Other Answers
You Might be Interested in
A freaction that is less than 5/6
Answers (1)
200 less than the number has 4 hundreds
Answers (1)
What's the contropositive of the statement if a month is June then it has 30 days
Answers (1)
256 equals j subtracted from 199
Answers (2)
12x+6y=24 solve for y
Answers (1)
New Questions in Mathematics
The teacher has 15 gold prize ribbons, 22 blue ribbons, and 5e red ribbons. There are 12 boys and 18 girls in the class.
Answers (1)
3 (6x^2-5x+7) - 2 (-4x^2+8-10)
Answers (1)
A model ship is built to a scale of 1 centimeter: 5 meters
Answers (1)
Simply: x^3 y^3 / x^3 y^2 (the arrows mean to the power of the number)
Answers (1)
A costumer is buying 3dvds that cost $6.55 each, with an additional 8% sales tax. What is the total amount that the costumer pays, rounded up to the nearest cent
Answers (1)
Home » Mathematics » In a triangle ABC, AB = 7, AC = 8, BC = 3, what is cos (A) ?
Sign Up Forgot Password?