A gardener is planting two types of trees:

Type A is 3 feet tall and grows at a rate of 21 inches per year.

Type B is 8 feet tall and grows at a rate of 15 inches per year.

Algebraically determine exactly how many years it will take for these trees to be the same height.

Question

Charlotte Cooke

Mathematics

27 May, 12:55

A gardener is planting two types of trees:

Type A is 3 feet tall and grows at a rate of 21 inches per year.

Type B is 8 feet tall and grows at a rate of 15 inches per year.

Algebraically determine exactly how many years it will take for these trees to be the same height.

+2

Answers (2)

Know the Answer?

Loki · Answer 1

10 years

Step-by-step explanation:

let they become of same height after t years

3ft=36 inches

hence

height of A

Ha=36+21t

8ft=96 inches

height of B

Hb = 96+15t

as Ha = Hb

36+21t = 96+15t

21t-15t = 96-36

6t=60

t=60/6

t = 10 years

Levi Burns · Answer 2

Answer: It'll take 11 years for them to be the same height at 20 feet and 6 inches.

A gardener is planting two types of trees:Type A is 3 feet tall and grows at a rate of 21 inches per year.Type B is 8 feet tall and grows at a rate of 15 inches per year.Algebraically determine exactly how many years it will take for these trees to be the same height.

A gardener is planting two types of trees:

Type A is 3 feet tall and grows at a rate of 21 inches per year.

Type B is 8 feet tall and grows at a rate of 15 inches per year.

Algebraically determine exactly how many years it will take for these trees to be the same height.