If $f (x) = ax^6-bx^4+x-1$ and $f (2) = 5$, then what is the value of $f (-2) $?

Question

Jonas Massey

Mathematics

22 April, 08:30

If $f (x) = ax^6-bx^4+x-1$ and $f (2) = 5$, then what is the value of $f (-2) $?

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Answers (1)

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Deandre Ashley · Answer 1

f (-2) = 1

Step-by-step explanation:

The unknown terms are of even degree, so will have the same value for x=2 and x=-2. If we call those terms Q, then ...

... f (2) = Q + 2 - 1 = 5

... Q = 4

... f (-2) = Q - 2 - 1 = 4 - 3

... f (-2) = 1