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30 January, 08:16

The length of a rectangular field is represented by the expression 14x-3x^2+2y. The width of the field is represented by the expression 5x-7x^2+7y. How much greater is the length of the field than the width?

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  1. 30 January, 08:30
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    9x+4x^2-5y

    You subtract like from like.

    14x-5x = 9x

    -3x^2--7x^2 = 4x^2

    2y-7y=5y
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