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25 June, 13:15

If f (3x - 1) = 6x - 1, find f (x) and f (0)

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  1. 25 June, 13:18
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    f (3x - 1) = 6x - 1

    Rewrite 6x - 1 as a function of 3x - 1:

    6x - 1 = 6x - 2 + 1 = 2 (3x - 1) + 1

    That is,

    f (3x - 1) = 2 (3x - 1) + 1

    which means

    f (x) = 2x + 1

    and so

    f (0) = 2*0 + 1 = 1
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