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Carlie Schmitt
Mathematics
25 June, 13:15
If f (3x - 1) = 6x - 1, find f (x) and f (0)
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Mylie Carey
25 June, 13:18
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f (3x - 1) = 6x - 1
Rewrite 6x - 1 as a function of 3x - 1:
6x - 1 = 6x - 2 + 1 = 2 (3x - 1) + 1
That is,
f (3x - 1) = 2 (3x - 1) + 1
which means
f (x) = 2x + 1
and so
f (0) = 2*0 + 1 = 1
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