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27 January, 19:23

Use the quadratic formula to solve the equation, which has one solution. y^2+2y+1=0 Enter your answer in the box. Write the number only. Do not include "y = " in your answer.

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  1. 27 January, 19:39
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    Answer: the solutions the equation is - 3 or 5

    Step-by-step explanation:

    The given quadratic equation is expressed as

    y² + 2y - 1 = 0

    The equation is already in the standard form of ax² + bx + c

    The general formula for solving quadratic equations is expressed as

    x = [ - b ± √ (b² - 4ac) ]/2a

    From the equation given,

    a = 1

    b = 2

    c = - 1

    Therefore, it becomes

    = [ - 2 ± √ (2² - 4 * 1 * - 1) ]/2 * - 1

    = [ - 2 ± (8) ] / - 2

    = ( - 2 + 8) / - 2. Or ( - 2 - 8) / - 2

    = 6 / - 2 or - 10 / - 2

    = - 3 or 5
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