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3 April, 00:57

A die is rolled twice. What is the probability of showing a 1 on the first roll and an even number on the second roll?

Durian

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Answers (2)
  1. 3 April, 01:01
    0
    Answer: 1/12

    Step-by-step explanation:

    The sample space when a die is rolled twice is given below:

    1 2 3 4 5 6

    1 1,1 1,2 1,3 1,4 1,5 1,6

    2 2,1 2,2 2,3 2,4 2,5 2,6

    3 3,1 3,2 3,3 3,4 3,5 3,6

    4 4,1 4,2 4,3 4,4 4,5 4,6

    5 5,1, 5,2 5,3 5,4 5,5 5,6

    6 6,1 5,2 6,3 6,4 6,5 6,6

    Those showing a one on the first throw and an even number on the second roll are:

    { 1,2 : 1,4 : 1,6}

    Therefore:

    the probability of showing a 1 on the first roll and an even number on the second roll = 3/36

    = 1/12
  2. 3 April, 01:12
    0
    1/12

    Step-by-step explanation:

    Okay, so this will be a compound probability question because there are two parts to the question.

    Firstly, a die has 6 sides, and there is only one chance of getting a 1, so the probability would be 1/6.

    Furthermore, there are 3 different even numbers on a 6-sided die, so that is 3/6, which can be simplified to 1/2.

    Now, because this is a compound probability, we have to multiply 1/2 and 1/6 together, which would give us our answer of 1/12.
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