Ask Question
27 May, 17:12

he Statue of Liberty is approximately 305 feet tall. If the angle of elevation of a ship to the top of the statue is 22.9 degrees , how far, to the nearest foot, is the ship from the statue's base?

+2
Answers (2)
  1. 27 May, 17:31
    0
    is at a distance of 722 feet

    Step-by-step explanation:

    we have the angle that forms between the water and the imaginary line between the ship and the tip of the statue

    we have the statue height that would be the opposite leg to our angle and we want to know the distance of the ship to the statue that would be the adjacent leg

    we see that it has (angle, adjacent, opposite)

    well to start we have to know the relationship between angles, legas and the hypotenuse

    a: adjacent

    o: opposite

    h: hypotenuse

    sin α = o/h

    cos α = a/h

    tan α = o/a

    it's the tangent

    tan α = o/a

    we replace the values and solve

    tan α = o/a

    tan 22.9 = 305/a

    a = 305/tan22.9

    a = 305/0.4224

    a = 722

    is at a distance of 722 feet
  2. 27 May, 17:37
    0
    722 feet

    Step-by-step explanation:

    Tan (22.9) = 305/base

    Base = 305/tan (22.9)

    Base = 722.036124

    To the nearest foot, 722 feet
Know the Answer?
Not Sure About the Answer?
Find an answer to your question 👍 “he Statue of Liberty is approximately 305 feet tall. If the angle of elevation of a ship to the top of the statue is 22.9 degrees , how ...” in 📗 Mathematics if the answers seem to be not correct or there’s no answer. Try a smart search to find answers to similar questions.
Search for Other Answers