An airplane begins its descent with an average speed of 240 mph at an angle of depression of 4°. how much altitude will the plane lose in 5 min. round to the nearest tenth of a mile.

Distance=speed*time

distance covered by plane in 5 min will be:

distance=240*5/60=20 miles

thus the altitude lost will be:

sin θ=opposite/hypotenuse

sin 4=h/20

h=20sin 4

h=1.395 miles~1.4 miles