The area of ΔABC = 14 ft2. If side a = 5 ft and angle C = 53°, find the measure of side b. Round your answer to the nearest tenth.

Area of triangle = (1/2) * a*b*sin (C)

14 = (1/2) * 5*b*sin (53)

14 = (1/2) * 5*sin (53) * b

14 = 1.99658877511823*b

b = 14/1.99658877511823

b = 7.01195968567488

b = 7.0

Side b is roughly 7.0 ft