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15 May, 06:06

A walking path is shaped like a rectangle with a width 7 times its length l. what is a simplified expression for the distance between opposite corners of the walking path?

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  1. 15 May, 06:28
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    The simplified expression is d = (5√2) L

    Step-by-step explanation:

    * Lets explain the problem

    - A walking path is shaped like a rectangle

    - The width of the rectangle is 7 times its length L

    ∵ The length of the rectangle is L

    ∵ The width is 7 times the length

    ∴ The width of the rectangle is 7L

    - The distance between the opposite corners represented by the

    diagonal of the rectangle

    - The length, the width and the diagonal formed a right triangle

    - Its hypotenuse is the diagonal of the rectangle

    - Its two legs are the length and the width of the rectangle

    * Now we have right triangle use the Pythagoras Theorem to find

    the hypotenuse

    ∵ The length, the width and the diagonal of the rectangle are the

    sides of a right triangle

    ∵ The diagonal is the hypotenuse (h) of the triangle

    ∵ hypotenuse = √[L² + W²]

    ∵ The length = L and the width = 7L

    ∴ h = √[ (L) ² + (7L) ²] = √[L² + 49L²] = √[50L²]

    ∵ √50 = 5√2

    ∵ √ (L²) = L

    ∴ h = 5√2 L

    ∵ The diagonal of the rectangle is the distance between the

    opposite corners

    ∴ The distance between the opposite corners is (5√2) L

    * The simplified expression is d = (5√2) L, where L is the length

    of the rectangle
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