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19 May, 14:46

Simplify each of the following powers of i. i^99=

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Answers (2)
  1. 19 May, 14:53
    0
    -i is the answer
  2. 19 May, 14:56
    0
    I = sqrt (-1)

    If the power is

    - even then the value could be - 1 or 1

    -odd then the value could be - i or i

    99 is odd so now is

    -i if (99+1) / 2 is even or is

    i is (99+1) / 2 is odd

    Now check (99+1) / 2 = 100/2 = 50,

    50 is even so

    i^99 = - i
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