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23 March, 20:14

Given that f (x) = x2 - 4x - 3 and g (x) = the quantity of x plus three, over four, solve for f (g (x)) when x = 9.

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  1. 23 March, 20:37
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    If x = 9 then it would go f (x) = (9) 2 - 4 (9) - 3 = 15

    f (x) = 15 x = 9 g (x) = 3 [x + 3 / 4, 12/4, 3]

    If x is 9 and f (x) is 15, f alone would be 6, f (g (x)) = 9
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