The angle of Inclination from the base of skyscraper A to the top of skyscraper B is approximately 11.9°. If Skyscraper B is 1424 feet tall, how far apart are the two skyscrapers? Assume

the bases of the two buildings are at the same elevation.

feet.

The distance from skyscraper A to skyscraper B is

(Round to two decimal places as needed.)

6757.36ft to 2dp

Step-by-step explanation:

For base distance there are different ways in trigonometry to find the base. For this finding we are given the height and opposite angle.

We can then calculate; using division 1424 / tan 11.9 = 6757.36427ft

For slope we can find Sin (11.9°) x 1424 to find 293.63ft.

It shows, 293.63476 on the calculator so the answer is kept at 293.63ft = left to 2dp (or 3524 inches) away

Step-by-step explanation:

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