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Isaias Watkins
Mathematics
12 October, 22:21
If DF=9x-39 and DE=47 and EF is 3x+10 find ef
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Amelie Hurley
12 October, 22:36
0
EF = 58
Step-by-step explanation:
Starting with the premise that
DF = DE + EF, then
9x - 39 = 47 + 3x + 10 (subtract 3x from both sides)
6x - 39 = 57 (add 39 to both sides)
6x = 96 (divide both sides by 6)
x = 16
Hence
EF = 3x + 10 = (3 * 16) + 10 = 48 + 10 = 58
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