Mary had $25,000 to invest. She invested part of that amount at 3% annual interest and part at 5% annual interest for one year. The amount of interest she earned for both investments was $1100. How much was invested at each rate?

Question

Reuben Bullock

Mathematics

11 February, 23:42

Mary had $25,000 to invest. She invested part of that amount at 3% annual interest and part at 5% annual interest for one year. The amount of interest she earned for both investments was $1100. How much was invested at each rate?

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Answers (1)

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Natalee Long · Answer 1

(25000-f) (.03) +.05f=1100

750-.03f+.05f=1100

750+.02f=1100

.02f=350

f=$17500

So Mary invested $17500 @ 5% and 7500 at 3% to earn $1100 in interest.