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13 July, 17:40

How do i solve 1/4 (x+3) - 4x<3 (1+x) ... its suppose to be a greater than or equal to sign

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  1. 13 July, 17:58
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    First, multiply 1/4 by x+3 ⇒ (1/4x+3/4). Next, multiply 3 by 1+x ⇒ (3+3x). The equation should now look like this: 1/4x+3/4-4x≤3+3x. The next thing you have to do is get all of the x's on one side of the symbol. Subtract 1/4x from both sides, and the equation then looks like this: 3/4-4x≤3+2 3/4x. Add the - 4x to both sides, and the equation should look like this: 3/4≤3+6 3/4x. Next, you have to move the 3 to the left side. To do that, subtract it from both sides. The equation then look like this: - 2 1/4≤6 3/4x. Then, to get the x alone, you need to divide the coefficient (6 3/4) by - 2 1/4, which equals - 1/3 or - 0.3 repeating. So, - 1/3≤x
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