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29 October, 20:16

The function is defined by f (x) = x^2+3x-10

if f (x+5) = x^2 + kx+30, k=

find the smallest zero of f (x+5). x=

+4
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  1. 29 October, 20:27
    0
    First you put (x+5) into the initial function wherever you see x so it becomes

    (x+5) ^2+3 (x+5) - 10=x^2+kx+30

    (x^2+5x+25) + (3x+15) - 10 simplified left side

    x^2+8x+30 fully simplified left side

    thus k=8

    x^2+8x+30=0 to find 0s

    -4 + 3.7416573867739i

    -4 - 3.7416573867739i

    these are the roots you find after using the quadratic formula

    the second one is the smallest
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