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15 September, 17:46

If h (x) = 3x - 1 and j (x) = - 2x, solve h[j (2) ] and select the correct answer below.

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Answers (2)
  1. 15 September, 18:02
    0
    h[j (2) ] = - 13.

    Step-by-step explanation:

    Given : If h (x) = 3x - 1 and j (x) = - 2x,

    To find : solve h[j (2) ].

    Solution : We have given

    h (x) = 3x - 1 and j (x) = - 2x

    For x = 2,

    j (2) = - 2 (2).

    j (2) = - 4.

    h[j (2) ] = h (-4).

    h (4) = 3 (-4) - 1.

    h (4) = - 12 - 1.

    h[j (2) ] = h (4) = - 13.

    h[j (2) ] = - 13.

    Therefore, h[j (2) ] = - 13.
  2. 15 September, 18:04
    0
    h[j (2) ] = -13

    Step-by-step explanation:

    The first step is to solve j (2) by putting x=2 into j (x)

    j (2) = - 2 (2) = - 4

    Now we put x = - 4 into h (x)

    h (-4) = 3 (-4) - 1

    h (-4) = - 12-1 = - 13

    h[j (2) ] = -13
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