A local hamburger shop sold a combined total of 600 hamburgers and cheeseburgers on Thursday. There were 50 more cheeseburgers sold than hamburgers. How many hamburgers were sold on Thursday?

Let t = the total number of hamburgers and cheeseburgers, c = the total number of cheeseburgers, and h = the total number of hamburgers.

t = c + h where t = 600

c = h + 50

Use substitution to solve for h:

600 = (h+50) + h

600 = 2h+50

600-50=2h

550=2h

550/2=2h/2

h=275

therefore, 275 hamburgers were sold on thursday.