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Kendal Stokes
Mathematics
26 February, 15:54
How to solve this equation 2 (f+3) + 4f=6+6f?
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Stevens
26 February, 16:02
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2f+6+4f=6+6f
6f+6-6=6-6+6f
6f=6f
This means f can equal any number which we call mathematically infinite solution or infinitely many solutions
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Abel Adkins
26 February, 16:17
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Step 1: Simplify both sides of the equation.
2 (f+3) + 4f=6+6f
Simplify: (Show steps)
6f+6=6f+6
Step 2: Subtract 6f from both sides.
6f+6-6f=6f+6-6f
6=6
Step 3: Subtract 6 from both sides.
6-6=6-6
0=0
Answer:
All real numbers are solutions.
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