If the length I of a rectangle is 3 more than twice the width w. The area is 90. Find the width

w = 6

Step-by-step explanation:

Givens

Area = 90

Let the width = w

Let the length = 2w + 3

Formula

Area = L * W

Solution

Area = (2w + 3) * w

Area = (2w + 3) * w = 90 Remove the brackets.

Area = 2w^2 + 3w = 90 Subtract 90 from both sides.

2w^2 + 3w - 90 = 0

This will factor into

(w - 6) (2w + 15) = 0

Only w - 6 will = a zero that makes sense when speaking of an area

w - 6 = 0

w = 6

L = 2*w + 3

L = 2*6 + 3

L = 15

The width is 6