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25 October, 08:12

Wonton set his watch 8seconds behind, and it falls behind another 1 second everyday. How far behind is wontons watch if he last set it 26 days ago

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  1. 25 October, 08:33
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    To figure out the answer to this problem, we must first create a formula. the formula is going to be y=x+8.

    -y is the amount of seconds behind

    -x is the amount of days since it has last been set

    -8 is how many seconds it's already behind

    to solve, we need to fill in for x then solve the equation:

    y=x+8

    y=26+8

    y=34

    that means that wonton's watch is 34 seconds behind.
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