ASB is selling In-N-Out as a fundraiser. Fries cost $2 and shakes cost $3. Students can only buy one item each. ASB wants to know which sells better but they lose track of what they sold. They know 105 students bought either fries or a shake. They count their money and it's $245. How many fries (x) and shakes (y) did they sell?

Question

Rhett Montes

Mathematics

9 July, 14:21

ASB is selling In-N-Out as a fundraiser. Fries cost $2 and shakes cost $3. Students can only buy one item each. ASB wants to know which sells better but they lose track of what they sold. They know 105 students bought either fries or a shake. They count their money and it's $245. How many fries (x) and shakes (y) did they sell?

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Answers (1)

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Eleanor · Answer 1

70 fries and 35 shakes

Step-by-step explanation:

ASB is selling In-N-Out as a fundraiser. Fries cost $2 and shakes cost $3. Students can only buy one item each. ASB wants to know which sells better but they lose track of what they sold. They know 105 students bought either fries or a shake. They count their money and it's $245. How many fries (x) and shakes (y) did they sell?

f = fries

s = shakes

To solve this we need to make two equations. Those equations being: f+s = y and 2f+3s = y. Now we will plug in all the values. f + s = 105 and 2f + 3s = 245. Now we will subtract f from 105 to get s. this makes s = 105-f. We can then plug this into the other equation making the other equation: 2f + 3 (105-f) = 245. Now we will simplify this to get: 2f + (315 - 3f) = 245. When we simplify it further we get: 315-f = 245. Now we will subtract 315 from both sides to get: - f = - 70. now divide both sides by - 1 and we get f = 70. Now we can plug that into the f + s = y equation. 70 + s = 105. Subtract 70 from both sides and we have s. S = 35