A taxi company charges a fixed hire fee (which is a whole number of dollars) plus a rate for each

kilometer (which is a multiple of 10¢ and more than the set national minimum rate of $1.75),

rounded up to the nearest kilometer.

Maira's last journey cost $37.90, but she does not know how far it was, or what the fixed hire fee

is. She wants to know how far the journey was.

She has a previous bill from the same taxi company, for a different journey, for $21.80.

How far was her last journey?

Question

Wayne Doyle

Mathematics

3 April, 06:16

A taxi company charges a fixed hire fee (which is a whole number of dollars) plus a rate for each

kilometer (which is a multiple of 10¢ and more than the set national minimum rate of $1.75),

rounded up to the nearest kilometer.

Maira's last journey cost $37.90, but she does not know how far it was, or what the fixed hire fee

is. She wants to know how far the journey was.

She has a previous bill from the same taxi company, for a different journey, for $21.80.

How far was her last journey?

+5

Answers (1)

Know the Answer?

Eli Kline · Answer 1

362 kilometre

Step-by-step explanation:

Let a be the total cost of a journey

let b represent the total distance of a journey

$1.75 is a fixed charge of a journey

the additional charge is $0.10 for b distance, hence total of additional charge is $.10 multiplied by b i. e 0.1 b

a=1.75+0.1b

a = 37.90

37.90=1.75+0.1b

0.1b=37.90-1.75

0.1 b=36.15

b=36.15 / 0.10

b=361.5

b=362 kilometre

For the journey that cost 21.80

21.80=1.75+0.1 b

0.1 b=21.80-1.75

0.1 b=20.05

b=20.05 / 0.1

b=200.5

b = 201 kilometre