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9 April, 21:20

A parabola opening up or down has vertex (0, - 1) and passes through (6,

-

10). Write its equation in vertex form.

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  1. 9 April, 21:37
    0
    y + 1 = (11/36) (x - 0) ^2

    Step-by-step explanation:

    Suppose that the parabola opens UP. We adapt the equation

    y - k = a (x - h) ^2 as follows: k = 0 because the vertex is at (0, - 1); also h = 1.

    Then we have:

    y + 1 = a (x - 0) ^2

    We are told that (6, 10) is on the parabola. Subtracting 6 for x and 10 for y, we get:

    10 + 1 = a (6 - 0) ^2, or 11 = a (6^2)

    Then 11/36 = a

    The equation of the parabola in vertex form is y + 1 = (11/36) (x - 0) ^2
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