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14 March, 00:15

1+3+5+7 + ... + 1003 = what is the answer?

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  1. 14 March, 00:36
    0
    1 + (n-1) d = 1003

    (n-1) 2 = 1002

    n-1 = 501

    n=502

    Sum = 502 (1+1003) / 2 = 253,004
  2. 14 March, 00:43
    0
    a) 1 + 2 + 3 + 4 + ... + 98

    98 + 97 + 96 + 95 + ... + 1

    sum 99 + 99 + 99 + 99 + ... + 99

    there are 98 of these sums, the total is 98 * 99 = 9702, since this sum is twice the sum of the numbers 1 thru 98, we have

    sum 1 + 2 + 3 + 4 + ... 98 = 9702/2 = 4851

    b) 1 + 3 + 5 + 7 + ... + 1003

    1003 + 1001 + 999 + 997 + ... + 1

    sum 1004 + 1004 + 1004 + 1004 + ... 1004

    There are 502 of these sums. the total is 502 * 1004 = 504008, since this sum is twice the sum of the numbers 1 + 3 + 5 + 7 + ... 1003, we have

    sum 1 + 3 + 5 + 7 + ... + 1003 = 504008/2 = 252004
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