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15 February, 08:38

Bob raises Guinea Pigs and Chinchillas on his beachfront oasis. There are a total of 60,005 animals at the oasis. The number of Chinchillas is 5 more than 2 times the number of guinea pigs. How many of each animals are there? Let g = the number of guinea pigs and let c = the number of chinchillas. Write a system of equations to represent the situation and use substitution to solve for the amount of each animal.

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  1. 15 February, 08:42
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    Let named variables as you said g - guinea pigs and c - chinchillas

    System of equation is:

    First is: c + g = 60,005

    Second is: c = 2g+5

    When we replace second in first we get:

    2g+5+g = 60,005 = > 3g+5 = 60,005 = > 3g = 60,000

    g=60.000/3 = 20,000 = > g=20,000

    When this result we replace in the second equation we get

    c = 2 * 20,000 + 5 = 40,000+5 = 40,005

    c = 40,005

    Good luck!
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