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25 May, 08:51

Jillian's school is selling tickets for a play. The tickets cost $10.50 for adults and $3.75 for students. The ticket sales for opening night totaled $2071.50. The equation 10.50 a plus 3.75 b equals 2071.50, where a is the number of adult tickets sold and b is the number of student tickets sold, can be used to find the number of adult and student tickets. If 82 students attended, how may adult tickets were sold?

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  1. 25 May, 09:07
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    The number of adults tickets sold = 168.

    Step-by-step explanation:

    The cost of 1 adult ticket = $10.50

    The cost of 1 student ticket = $3.75

    The total sales from the ticket = $2071.50

    Now, here let us assume

    The number of adult tickets sold = a

    The number of student tickets sold = b

    So, the equation is given as:

    10.50 a + 3.75 b = 2071.50

    Now, its given the number of students = 82

    ⇒ b = 82

    Putting the value of b in the above equation, w e get:

    10.50 a + 3.75 (82) = 2071. 50

    or, 10.50 a = 2071.50 - 307.5 = 1764

    or, a = 1764/10.5 = 168

    Hence, the number of adults tickets sold = a = 168.
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